Assume boolean algebra.
((x=(x=0)) ∧ (x=((x=0) ∨ (x=(x=(x=0))))))
Update 6/13/2026 –
Explanation: this is an attempt to formalize the liar’s sentence + liar’s revenge sentence in boolean algebra; I am far from certain I did so correctly.
Assume boolean algebra.
((x=(x=0)) ∧ (x=((x=0) ∨ (x=(x=(x=0))))))
Update 6/13/2026 –
Explanation: this is an attempt to formalize the liar’s sentence + liar’s revenge sentence in boolean algebra; I am far from certain I did so correctly.
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